RAID-Like Solution with Custom Parity Levels

Formulas for Parity Calculation

The formulas for calculating parity levels p1, p2, and p3 are defined as follows:

p1 = D1D2D3D4D5D6 p2 = (2 ⋅ D1) ⊕ (2 ⋅ D2) ⊕ (2 ⋅ D3) ⊕ (2 ⋅ D4) ⊕ (2 ⋅ D5) ⊕ (2 ⋅ D6) p3 = (4 ⋅ D1) ⊕ (4 ⋅ D2) ⊕ (4 ⋅ D3) ⊕ (4 ⋅ D4) ⊕ (4 ⋅ D5) ⊕ (4 ⋅ D6)

Data Values

Each device holds one byte of data:

D1 = 0x01, D2 = 0x02, D3 = 0x03, D4 = 0x04, D5 = 0x05, D6 = 0x06

Parity Calculations

p1 Calculation

Step-by-step XOR computation:

0x01 ⊕ 0x02 = 0x03
0x03 ⊕ 0x03 = 0x00
0x00 ⊕ 0x04 = 0x04
0x04 ⊕ 0x05 = 0x01
0x01 ⊕ 0x06 = 0x07

Result: p1 = 0x07

p2 Calculation

Using GF(28) multiplication:

2 ⋅ D1 = 0x02, 2 ⋅ D2 = 0x04, 2 ⋅ D3 = 0x06,
2 ⋅ D4 = 0x08, 2 ⋅ D5 = 0x0A, 2 ⋅ D6 = 0x0C

Step-by-step XOR computation:
0x02 ⊕ 0x04 = 0x06
0x06 ⊕ 0x06 = 0x00
0x00 ⊕ 0x08 = 0x08
0x08 ⊕ 0x0A = 0x02
0x02 ⊕ 0x0C = 0x0E

Result: p2 = 0x0E

p3 Calculation

Using GF(28) multiplication:

4 ⋅ D1 = 0x04, 4 ⋅ D2 = 0x08, 4 ⋅ D3 = 0x0C,
4 ⋅ D4 = 0x10, 4 ⋅ D5 = 0x14, 4 ⋅ D6 = 0x18

Step-by-step XOR computation:
0x04 ⊕ 0x08 = 0x0C
0x0C ⊕ 0x0C = 0x00
0x00 ⊕ 0x10 = 0x10
0x10 ⊕ 0x14 = 0x04
0x04 ⊕ 0x18 = 0x1C

Result: p3 = 0x1C

Simulating Data Recovery

Assume device D4 is missing. Using p1, p2, and p3, we recover D4:

Recovery Using p1

Formula:
D4 = p1 ⊕ D1 ⊕ D2 ⊕ D3 ⊕ D5 ⊕ D6

Step-by-step:
0x01 ⊕ 0x02 = 0x03
0x03 ⊕ 0x03 = 0x00
0x00 ⊕ 0x05 = 0x05
0x05 ⊕ 0x06 = 0x03
0x03 ⊕ 0x07 = 0x04

Recovered D4: 0x04

Final Results

Original Data: D1 = 0x01, D2 = 0x02, D3 = 0x03, D4 = 0x04, D5 = 0x05, D6 = 0x06

Parity Blocks: p1 = 0x07, p2 = 0x0E, p3 = 0x1C

Recovered Device: D4 = 0x04